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The molal elevation constant of water $=0.52^{\circ} \mathrm{C}$. The boiling point of 1.0 molal aqueous $\mathrm{KCl}$ solution (assuming complete dissociation of $\mathrm{KCl}$ ), therefore, should be
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$101.04^{\circ} \mathrm{C}$
$\begin{aligned} & \Delta T_b=i m k_b=0.52 \times 1 \times 2=1.04 \\ & T_b=100+1.04=101.04^{\circ} \mathrm{C} .\end{aligned}$
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