The molar conductivity of 0.025 mol L -1 methanoic acid is 46.1 S cm 2 mol -1 . Calculate its degree of dissociation and dissociation constant. Given λ o (H + ) = 349.6 S cm 2 mol -1 and λ o (HCOO - ) = 54.6 S cm 2 mol -1

Question

The molar conductivity of 0.025 mol L -1 methanoic acid is 46.1 S cm 2 mol -1 . Calculate its degree of dissociation and dissociation constant. Given λ o (H + ) = 349.6 S cm 2 mol -1 and λ o (HCOO - ) = 54.6 S cm 2 mol -1, Degree of dissociation = 0.013, Dissociation constant = 1.8 x 10 -3, Degree of dissociation = 0.114, Dissociation constant = 3.7 x 10 -4, Degree of dissociation = 0.024, Dissociation constant = 3.2 x 10 -3, Degree of dissociation = 0.024, Dissociation constant = 1.1 x 10 -3

MARKS App · Accepted Answer

Correct Option is : (B) Degree of dissociation = 0.114, Dissociation constant = 3.7 x 10 -4

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