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Question: Answered & Verified by Expert
The molar solubility product is $\mathrm{K}_{\mathrm{sp}}$. ' $\mathrm{s}$ ' is given in terms of $\mathrm{K}_{\mathrm{sp}}$ by the relation
ChemistryIonic EquilibriumJEE Main
Options:
  • A
    $\mathrm{s}=\left(\frac{\mathrm{K}_{\mathrm{sp}}}{128}\right)^{1 / 4}$
  • B
    $\mathrm{s}=\left(\frac{\mathrm{K}_{\mathrm{sp}}}{256}\right)^{1 / 5}$
  • C
    $\mathrm{S}=\left(256 \mathrm{~K}_{\mathrm{sp}}\right)^{1 / 5}$
  • D
    $\mathrm{s}=\left(128 \mathrm{~K}_{\mathrm{sp}}\right)^{1 / 4}$
Solution:
2862 Upvotes Verified Answer
The correct answer is:
$\mathrm{s}=\left(\frac{\mathrm{K}_{\mathrm{sp}}}{256}\right)^{1 / 5}$
$\mathrm{Ksp}=108 s^5$
$1 \times 4^4 \times s^{1+4}=256 s^5=\mathrm{Ksp}$

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