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The molarity of the solution when $4.9 \mathrm{~g}$ of $\mathrm{H}_2 \mathrm{SO}_4$ dissolved in $250 \mathrm{~mL}$ of solution is
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$0.2$
Molarity $=\frac{\frac{4.9 \mathrm{~g}}{98.0 \mathrm{~g} \mathrm{~mol}^{-1}}}{0.250 \mathrm{~L}}=0.2 \mathrm{~mol} \mathrm{~L}^{-1}$
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