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The moment of inertia of a body about the given axis, rotating with angular velocity $1 \mathrm{rad} / \mathrm{s}$ is numerically equal to ' $\mathrm{P}$ ' times its rotational kinetic energy. The value of ' $\mathrm{P}$ ' is
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The correct answer is:
$2$
The angular velocity
$$
\begin{aligned}
& \omega=1 \mathrm{rad} / \mathrm{s} \\
& I=P \cdot\left(\frac{1}{2} I \omega^2\right) \\
& \therefore P=2
\end{aligned}
$$
$$
\begin{aligned}
& \omega=1 \mathrm{rad} / \mathrm{s} \\
& I=P \cdot\left(\frac{1}{2} I \omega^2\right) \\
& \therefore P=2
\end{aligned}
$$
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