Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The moment of inertia of a disc about an axis passing through its centre and normal to its plane is I . The disc is now folded along a diameter such that the two halves are mutually perpendicular. Its moment of inertia about this diameter will now be
PhysicsRotational MotionNEET
Options:
  • A I
  • B I2
  • C I2
  • D I4
Solution:
2010 Upvotes Verified Answer
The correct answer is: I2
moment of inertia of a disc about an axis passing through its centre and normal to its plane

I=12mR2

The disc is now folded along a diameter such that the two halves are mutually perpendicular

In this moment of inertia about this diameter I=Id+Id

I=2Id

Id=12I

For a diameter; Id=I2

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.