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The moment of inertia of a thin uniform rod of mass $M$ and length $L$ about an axis passing through its mid-point and perpendicular to its length is $I_0$. Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is
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Verified Answer
The correct answer is:
$I_0+M L^2 / 4$
The theorem of parallel axis for moment of inertia.
$$
\begin{aligned}
& I=I_{\mathrm{CM}}+M h^2 \\
& I=I_0+M\left(\frac{L}{2}\right)^2
\end{aligned}
$$
$$
I=I_0+\frac{M L^2}{4}
$$
$$
\begin{aligned}
& I=I_{\mathrm{CM}}+M h^2 \\
& I=I_0+M\left(\frac{L}{2}\right)^2
\end{aligned}
$$
$$
I=I_0+\frac{M L^2}{4}
$$
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