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The moment of inertia of a uniform circular disc of radius $R$ and mass $M$ about an axis passing from the edge of the disc and normal to the disc is
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$\frac{3}{2} M R^2$
The moment of inertia of uniform circular disc about an axis through its centre and normal to its plane
$I_{\mathrm{CG}}=\frac{1}{2} M R^2$
According to theorem of parallel axis, the moment of inertia of the uniform circular disc about an axis passing from the edge of the disc fand normal to the disc,
$I=I_{\mathrm{CG}}+M R^2=\frac{1}{2} M R^2+M R^2=\frac{3}{2} M R^2$
$I_{\mathrm{CG}}=\frac{1}{2} M R^2$
According to theorem of parallel axis, the moment of inertia of the uniform circular disc about an axis passing from the edge of the disc fand normal to the disc,
$I=I_{\mathrm{CG}}+M R^2=\frac{1}{2} M R^2+M R^2=\frac{3}{2} M R^2$
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