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The momentum of a photon of energy 1 $\mathrm{MeV}$ in $\mathrm{kg} \mathrm{m} / \mathrm{s}$ will be:
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Verified Answer
The correct answer is:
$5 \times 10^{-22}$
Energy of photon $E=1 \mathrm{MeV}$
Momentum of photon $P=\frac{E}{C}$
$$
\begin{aligned}
P & =\frac{E}{C}=\frac{1 \times 10^6 \times 1.6 \times 10^{-19}}{3 \times 10^8} \\
& =5 \times 10^{-22} \mathrm{~kg} \mathrm{~m} / \mathrm{s}
\end{aligned}
$$
Momentum of photon $P=\frac{E}{C}$
$$
\begin{aligned}
P & =\frac{E}{C}=\frac{1 \times 10^6 \times 1.6 \times 10^{-19}}{3 \times 10^8} \\
& =5 \times 10^{-22} \mathrm{~kg} \mathrm{~m} / \mathrm{s}
\end{aligned}
$$
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