The motion of a particle executing SHM is given by x = 0.01 sin ⁡ 100 π ( t + 0.05 ) , where x is in metre and time t is in second. The time period is

Question

The motion of a particle executing SHM is given by x = 0.01 sin ⁡ 100 π ( t + 0.05 ) , where x is in metre and time t is in second. The time period is, 0 . 2 s, 0 . 1 s, 0 .0 2 s, 0 .0 1 s

MARKS App · Accepted Answer

x = 0.01 sin ⁡ 100 π t + 0.05 = 0.01 sin ⁡ ( 100 π t + 5 π ) ∴ Angular frequency ω = 100 π = 2 π T or T = 2 100 = 0.02 s

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