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The negation of the statement pattern $\sim \mathrm{p} \vee(\mathrm{q} \rightarrow \sim \mathrm{r})$ is
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Verified Answer
The correct answer is:
$\mathrm{p} \wedge(\mathrm{q} \wedge \mathrm{r})$
(A)
$\begin{array}{l}
\sim[\sim p \vee(q \rightarrow \sim r)] \\
\equiv p \wedge \sim(q \rightarrow \sim r) \\
\equiv p \wedge \sim(\sim q \vee \sim r) \\
\equiv p \wedge \sim[\sim(q \wedge r)] \\
\equiv p \wedge(q \wedge r)
\end{array}$
$\begin{array}{l}
\sim[\sim p \vee(q \rightarrow \sim r)] \\
\equiv p \wedge \sim(q \rightarrow \sim r) \\
\equiv p \wedge \sim(\sim q \vee \sim r) \\
\equiv p \wedge \sim[\sim(q \wedge r)] \\
\equiv p \wedge(q \wedge r)
\end{array}$
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