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The negation of the statement, $\exists x \in A$ such that $x+5>8$ is
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The correct answer is:
$\forall x \in A, \quad x+5 \leq 8$
While doing negation we replace $\exists$ by $\forall$ and $>$ by $\leq$.
So required statement is $\forall \mathrm{x} \in \mathrm{A}$ such that $\mathrm{x}+5 \leq 8$
So required statement is $\forall \mathrm{x} \in \mathrm{A}$ such that $\mathrm{x}+5 \leq 8$
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