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The non-existence of $\mathrm{PbI}_{4}$ and $\mathrm{PbBr}_{4}$ is due to
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Both (a) and (b)
The non-existence of $\mathrm{PbI}_{4}$ and $\mathrm{PbBr}_{4}$ is probably due to the strong oxidising power of $\mathrm{Pb}^{4+}$ ions and strong reducing power of $\mathrm{I}$ and $\mathrm{Br}^{-}$ions.
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