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The north pole of a long horizontal bar magnet is being brought closer to a vertical conducting plane along the perpendicular direction. The direction of the induced current in the conducting plane will be
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According to Lenz's law
$e=-N\left(\frac{\Delta B}{\Delta t}\right) \cdot A \cos \theta$
$e=-N\left(\frac{\Delta B}{\Delta t}\right) \cdot A \cos \theta$
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