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The number of angular and radial nodes of $4 d$ orbital respectively are
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The correct answer is:
3,1
For $4 d$ orbital, $n=4, /=2$
Number of angular node $=I=2$
Number of radial node $=n-I-1=4-2-1=1$
Number of angular node $=I=2$
Number of radial node $=n-I-1=4-2-1=1$
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