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The number of anti-bonding electrons present in $\mathrm{O}_{2}^{-}$molecular ion is
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The correct answer is:
5
$\mathrm{MO}$ configuration of $\mathrm{O}_{2}^{+}$molecular ion :
$\sigma 1 s^{2}, \sigma^{*} s^{2}, \sigma 2 s^{2}, \overbrace{}^{*} 2 s^{2}, \sigma 2 p_{x}^{2}, \pi 2 p_{y}^{2}=\pi 2 p_{z}^{2}, \stackrel{*}{\pi} 2 p_{y}^{1}$
Hence, number of antibonding electrons
$=2(1 s)+2(2 s)+1(2 p)=5$
$\sigma 1 s^{2}, \sigma^{*} s^{2}, \sigma 2 s^{2}, \overbrace{}^{*} 2 s^{2}, \sigma 2 p_{x}^{2}, \pi 2 p_{y}^{2}=\pi 2 p_{z}^{2}, \stackrel{*}{\pi} 2 p_{y}^{1}$
Hence, number of antibonding electrons
$=2(1 s)+2(2 s)+1(2 p)=5$
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