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The number of arrangements of the letters of the word ARRANGEMENT in which two Es' do not occur adjacently is
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Verified Answer
The correct answer is:
$\frac{9}{16}(10) !$
Total arrangements $=\frac{\lfloor 11}{\lfloor 2 \cdot 2 \cdot|2 \cdot| 2}$
Number of arrangement in which two E occur together $=\frac{10}{2 \cdot 2 \cdot 2 \cdot 2}$ $=\frac{10.9}{16}=\frac{9}{16}\lfloor 10$
Number of arrangement in which two E occur together $=\frac{10}{2 \cdot 2 \cdot 2 \cdot 2}$ $=\frac{10.9}{16}=\frac{9}{16}\lfloor 10$
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