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Question: Answered & Verified by Expert
The number of correct statements from the following is ...........
A. For 1s orbital, the probability density is maximum at the nucleus
B. For 2s orbital, the probability density first increases to maximum and then decreases sharply to zero.
C. Boundary surface diagrams of the orbitals encloses a region of 100% probability of finding the electron.
D. p and d-orbitals have 1 and 2 angular nodes respectively
E. probability density of p-orbital is zero at the nucleus
 
ChemistryStructure of AtomJEE MainJEE Main 2023 (11 Apr Shift 2)
Solution:
1847 Upvotes Verified Answer
The correct answer is: 3

Probability density curves for 1s2s and 2p orbitals are given below.

For 1s orbital, the probability density is maximum at the nucleus. For 2s orbital, the probability density first decreases and then increases. At any distance from nucleus the probability density of finding electron is never zero, and it always have some finite value. The number of angular nodes are equal to azimuthal quantum number. For p-orbital it is equal to 1 and for d-orbital it is equal to 2. Probability density of p-orbital is zero at the nucleus

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