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The number of different 9 digit number that can be formed, from the digits of the number 445577888 by rearranging its digits, so that the odd digits occupy even positions, are
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The correct answer is:
$60$
ways
and remaing five even digits $4,4,8,8,8$ can be arranged in 5 places in $\frac{\underline{5}}{2 \underline{3}}$
Hence total no of ways $=\frac{\lfloor 4}{\lfloor 2 L 2} \times \frac{\underline{5}}{2 \underline{2} \underline{3}}=6 \times 10=60$
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