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The number of different ways of preparing a garland using 6 distinct white roses and 5 distinct red roses such that no two red roses come together is
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The correct answer is:
43200
Given, White roses $=6$
Red roses $=5$
$\therefore \quad$ Total number of ways for making garlands such that no two red roses come together is
$$
=\frac{6 ! \times 5 !}{2}=43200
$$
Red roses $=5$
$\therefore \quad$ Total number of ways for making garlands such that no two red roses come together is
$$
=\frac{6 ! \times 5 !}{2}=43200
$$
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