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The number of electrons in $1 \mathrm{C}$ of charges is
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$6.25 \times 10^{18}$
Charge, $q=1 \mathrm{C}$
If $n$ be the total number of electrons in $1 \mathrm{C}$ of charge, then $q=n e$
$\begin{aligned} \Rightarrow \quad n &=\frac{q}{e} \\ &=\frac{1}{1.6 \times 10^{-19}} \\ &=6.25 \times 10^{18} \text { electrons } \end{aligned}$
If $n$ be the total number of electrons in $1 \mathrm{C}$ of charge, then $q=n e$
$\begin{aligned} \Rightarrow \quad n &=\frac{q}{e} \\ &=\frac{1}{1.6 \times 10^{-19}} \\ &=6.25 \times 10^{18} \text { electrons } \end{aligned}$
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