The number of geometric isomers that can exist for square planar P t C l p y N H 3 N H 2 O H + is (py = pyridine):

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The number of geometric isomers that can exist for square planar

{[P t (C l) (p y) (N H_{3}) (N H_{2} O H)]}^{+}

is (py = pyridine):

ChemistryCoordination CompoundsNEET

Options:

A 6
B 2
C 3
D 4

Solution:

1031 Upvotes Verified Answer

The correct answer is: 3

Complex with general formula [Mabcd]⁺ square planar complex can have three isomers.

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