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The number of geometrical isomers of $\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CHCl}$ is
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8
The given structure has three double bonds whose each carbon atom is differently substituted hence number of geometrical isomers will be $2^{\mathrm{n}}=2^{3}{ }^{3}=8$, where $n$ is the number of double bonds whose each carbon atom is differently substituted.
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