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The number of hydroxide ions, produced by one molecule of sodium carbonate $\left(\mathrm{Na}_2 \mathrm{CO}_3\right)$ on hydrolysis is
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2
$\mathrm{Na}_2 \mathrm{CO}_3+2 \mathrm{H}_2 \mathrm{O} \rightarrow 2 \mathrm{NaOH}+\mathrm{H}_2 \mathrm{CO}_3$
and $2 \mathrm{NaOH} \rightleftharpoons \mathrm{Na}^{+}+2 \mathrm{OH}^{-}$
ionisation
Hence, it is clear that $2 \mathrm{OH}^{-}$ions will be formed on hydrolysis of one molecule of sodium corbonate.
and $2 \mathrm{NaOH} \rightleftharpoons \mathrm{Na}^{+}+2 \mathrm{OH}^{-}$
ionisation
Hence, it is clear that $2 \mathrm{OH}^{-}$ions will be formed on hydrolysis of one molecule of sodium corbonate.
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