The number of integers x satisfying - 3 x 4 + det 1 x x 2 1 x 2 x 4 1 x 3 x 6 = 0 is equal to

Question

The number of integers x satisfying - 3 x 4 + det 1 x x 2 1 x 2 x 4 1 x 3 x 6 = 0 is equal to, 1, 2, 5, 8

MARKS App · Accepted Answer

Given, - 3 x 4 + det 1 x x 2 1 x 2 x 4 1 x 3 x 6 = 0 ⇒ x 8 + x 5 + x 5 - x 4 - x 7 - x 7 = 3 x 4 ⇒ x 8 - 2 x 7 + 2 x 5 - 4 x 4 = 0 ⇒ x 4 x 4 - 2 x 3 + 2 x - 4 = 0 ⇒ x 4 x 3 x - 2 + 2 x - 2 = 0 ⇒ x 4 x 3 + 2 x - 2 = 0 ∵ x is an integer, so x = 0 , 2 .

Search any question & find its solution

Looking for more such questions to practice?