Search any question & find its solution
Question:
Answered & Verified by Expert
The number of ions from the following that have the ability to liberate hydrogen from a dilute acid is _____.
\(\mathrm{Ti}^{2+}, \mathrm{Cr}^{2+}\) and \(\mathrm{V}^{2+}\)
Options:
\(\mathrm{Ti}^{2+}, \mathrm{Cr}^{2+}\) and \(\mathrm{V}^{2+}\)
Solution:
2488 Upvotes
Verified Answer
The correct answer is:
3
The ions $\mathrm{Ti}^{+2}, \mathrm{~V}^{+2} \mathrm{Cr}^{+2}$ are strong reducing agents and will liberate hydrogen from a dilute acid, eg.
$2 \mathrm{Cr}_{\text {(aq.) }}^{+2}+2 \mathrm{H}_{(\text {aq.) }}^{+} \longrightarrow 2 \mathrm{Cr}_{(\text {aq.) }}^{+3}+\mathrm{H}_2(\mathrm{~g})$
$2 \mathrm{Cr}_{\text {(aq.) }}^{+2}+2 \mathrm{H}_{(\text {aq.) }}^{+} \longrightarrow 2 \mathrm{Cr}_{(\text {aq.) }}^{+3}+\mathrm{H}_2(\mathrm{~g})$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.