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Question: Answered & Verified by Expert
The number of lone pairs of electrons present on $\mathrm{Xe}$ in $\mathrm{XeF}_4$ is
ChemistryChemical Bonding and Molecular StructureTS EAMCETTS EAMCET 2001
Options:
  • A $3$
  • B $4$
  • C $1$
  • D $2$
Solution:
2874 Upvotes Verified Answer
The correct answer is: $2$
Xe in ground state $\longrightarrow \ldots 5 s^2, 5 p^6, 5 d^6$
$X_e$ in IInd excited state $\longrightarrow \ldots 5 s^2, 5 p^4, 5 d^2$
$\longrightarrow \ldots .5 s^2, 5 p^4, 5 d^2$


Number of lone pairs $=2$
Number of bond pairs $=4$

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