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The number of moles of $\mathrm{KMnO}_{4}$ required to oxidize one equivalent of $\mathrm{Kl}$ in the presence of sulfuric acid is
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$1 / 5$
$\quad$ Valency factor of $\mathrm{KMnO}_{4}=5$
$5 \mathrm{e}^{-}+\mathrm{MnO}_{4}^{-}+8 \mathrm{H}^{+} \rightarrow \mathrm{Mn}^{+2}+4 \mathrm{H}_{2} \mathrm{O}$
$5 \mathrm{e}^{-}+\mathrm{MnO}_{4}^{-}+8 \mathrm{H}^{+} \rightarrow \mathrm{Mn}^{+2}+4 \mathrm{H}_{2} \mathrm{O}$
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