The number of neutrons emitted when $ { }_{92}^{235} \mathrm{U} $ undergoes controlled nuclear fission to $ { }_{54}^{142} \mathrm{Xe} $ and $ { }_{38}^{91} \mathrm{Sr} $ is

Question

The number of neutrons emitted when $ { }_{92}^{235} \mathrm{U} $ undergoes controlled nuclear fission to $ { }_{54}^{142} \mathrm{Xe} $ and $ { }_{38}^{91} \mathrm{Sr} $ is,

MARKS App · Accepted Answer

The nuclear reaction for the given case is, 9 2 U 2 3 5 + 0 n 1 → 9 2 U 2 3 6 → 5 4 Xe 1 4 2 + 3 8 Sr 9 1 + 3 0 n 1 Slow Unstable It is clear from the reaction that 3 neutrons are emitted in the reaction.

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