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Question: Answered & Verified by Expert

The number of paramagnetic species from the following is

Ni(CN)42-,Ni(CO)4,NiCl42-

Fe(CN)64-,CuNH342+

Fe(CN)63- and FeH2O62+

ChemistryCoordination CompoundsJEE MainJEE Main 2023 (25 Jan Shift 1)
Solution:
2940 Upvotes Verified Answer
The correct answer is: 4

Ni(CN)42-:Ni+2=

It is diamagnetic as  CN- is a strong field ligand and forces electron pairing.

Ni(CO)4:Ni=

It is diamagnetic as carbonyl group is a strong field ligand and forces electron pairing.

NiCl42-:Ni2+= 

It is paramagnetic as chloride group is a weak field ligand.

Fe(CN)64-:Fe2+ :

It is diamagnetic as CN is a  strong field ligand which causes pairing of electrons.

CuNH34+2:Cu+2 Here Copper ion has one unpaired electron, thus it is paramagnetic as it is 3d9 configuration.

Fe(CN)63-  :  Fe+3: 

It is paramagnetic, here CN- is a strong field ligand

FeH2O62+:Fe2+:

It is paramagnetic, here H2O , here a weak field ligand

 

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