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Question: Answered & Verified by Expert
The number of real values of x that satisfies the equation x4+4x3+12x2+7x-3=0 is 
MathematicsApplication of DerivativesJEE Main
Solution:
2478 Upvotes Verified Answer
The correct answer is: 2
Let, fx=x4+4x3+12x2+7x-3
f x =4 x 3 +12 x 2 +24x+7
f x =12 x 2 +2x+2
i.e. f''x>0, xR
Also, f0=-3

Hence, fx=0 has 2 real roots

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