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Question: Answered & Verified by Expert
The number of solutions of the equation tanxsinx-1=tanx-sinx, x0,2π is equal to.
MathematicsTrigonometric EquationsJEE Main
Options:
  • A 1
  • B 2
  • C 3
  • D 4
Solution:
1844 Upvotes Verified Answer
The correct answer is: 2
tanxsinx-tanx+sinx-1=0
tanx+1sinx-1=0
tanx=-1 or sinx=1 (Not possible as xπ2 )
Hence, for tanx=-1 there are 2 solutions in 0,2π

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