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The number of stereoisomer possible for the following compound is $\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}(\mathrm{Br})-\mathrm{CH}_{2}-\mathrm{CH}_{3}$
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The correct answer is:
4
$\mathrm{n}=2$ [No. of stereogenic area]
Total stereoisomer $=2^{\mathrm{n}}$
[When symm. is/are absent]
Total stereo isomer $=2^{2}=4$
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