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The number of terms in the expansion of $(x+y+z)^{10}$ is
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The correct answer is:
66
We have,
$(x+y+z)^{10}$
Total number of terms in the expansion of
$(x+y+z)^{10}={ }^{10+3-1} C_{3-1}={ }^{12} C_{2}=66$
$(x+y+z)^{10}$
Total number of terms in the expansion of
$(x+y+z)^{10}={ }^{10+3-1} C_{3-1}={ }^{12} C_{2}=66$
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