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The number of values of $x$ in the interval $[0,3 \pi]$ satisfying the equation $2 \sin ^2 x+5 \sin x-3=0$ is
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4
4
$2 \sin ^2 x+5 \sin x-3=0$
$\Rightarrow(\sin x+3)(2 \sin x-1)=0$
$\Rightarrow \sin x=\frac{1}{2} \quad \therefore \ln (0,3 \pi), x$ has 4 values
$\Rightarrow(\sin x+3)(2 \sin x-1)=0$
$\Rightarrow \sin x=\frac{1}{2} \quad \therefore \ln (0,3 \pi), x$ has 4 values
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