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The number of ways in which 5 boys and 4 girls sit around a circular tables. So, that no two girls sit together is
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The correct answer is:
$5 ! 4 !$
Number of ways in which the boys can be arranged $=4$ !
Number of ways in which girls alternately arranged $=5$ !
Total number of ways $=5 ! 4 !$
Number of ways in which girls alternately arranged $=5$ !
Total number of ways $=5 ! 4 !$
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