$5$ identical marbles can be distributed to $3$ boys, each receiving at least one in ${\mathrm{}}^{5-1}{C}_{3-1}={{}_{\mathrm{}}{}^{4}C}_2\mathrm{}$ ways
$4$ different toys can be grouped as $2,\mathrm{}1,\mathrm{}1$ in $\frac{4!}{2!1!1!}=\frac{4!}{2!}$ ways
Two boys will get $1$ each and they can be selected in ${}_{\mathrm{}}{}^3{C}_2$ ways.
Required number of ways $={{}_{\mathrm{}}{}^{4}C}_2\times \frac{4!}{2!}\times {{}_{\mathrm{}}{}^{3}C}_2=6\times 12\times 3=216$