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The orbital angular momentum of \( 3^{\text {rd }} \) orbital is equal to \( \sqrt{\mathrm{x}} \frac{\mathrm{h}}{2 \pi} \) the value of ' \( \mathrm{x} \) ' is
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The correct answer is:
6
Orbital angular momentum = ,
Equate with the given orbital angular momentum value, calculate the value of x as:
.
So,
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