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The order and degree of the differential equation $\left[1+\left[\frac{d y}{d x}\right]^{3}\right]^{\frac{7}{3}}=7 \frac{d^{2} y}{d x^{2}}$ are respectively.
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1,2
(D)
We have $\left[1+\left[\frac{d y}{d x}\right]^{3}\right]^{\frac{7}{3}}=7 \cdot \frac{d^{2} y}{d x^{2}}$
Cubing both sides, we get
$\left[1+\left[\frac{d y}{d x}\right]^{3}\right]^{7}=7\left[\frac{d^{2} y}{d x^{2}}\right]^{3}$
Hence order is 2 and degree is $3 .$
We have $\left[1+\left[\frac{d y}{d x}\right]^{3}\right]^{\frac{7}{3}}=7 \cdot \frac{d^{2} y}{d x^{2}}$
Cubing both sides, we get
$\left[1+\left[\frac{d y}{d x}\right]^{3}\right]^{7}=7\left[\frac{d^{2} y}{d x^{2}}\right]^{3}$
Hence order is 2 and degree is $3 .$
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