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The order and degree of the differential equation $\frac{d^2 y}{d x^2}=\sqrt{\frac{d y}{d x}}$ are respectively
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2,2
$\begin{aligned} & \frac{d^2 y}{d x^2}=\sqrt{\frac{d y}{d x}} \\ & \therefore \quad\left(\frac{d^2 y}{d x^2}\right)=\frac{d y}{d x} \\ & \therefore \text { order }=2 \text { and degree }=2\end{aligned}$
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