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The order and the degree of the differential equation $\left[1+\left(\frac{d y}{d x}\right)^{3}\right]^{\frac{7}{3}}=7\left(\frac{d^{2} y}{d x^{2}}\right)$ are respectively
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The correct answer is:
2,3
We have $\left[1+\left(\frac{d y}{d x}\right)^{3}\right]^{\frac{7}{3}}=7\left(\frac{d^{2} y}{d x^{2}}\right)$ Raising both sides to power of 3 , we get
$$
\left[1+\left(\frac{d y}{d x}\right)^{3}\right]^{7}=(7)^{3}\left(\frac{d^{2} y}{d x^{2}}\right)^{3}
$$
Hence order $=2$, degree $=3$
$$
\left[1+\left(\frac{d y}{d x}\right)^{3}\right]^{7}=(7)^{3}\left(\frac{d^{2} y}{d x^{2}}\right)^{3}
$$
Hence order $=2$, degree $=3$
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