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Question:
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The order of boiling points of the following compounds is
1. \(\left(\mathrm{CH}_3\right)_3 \ddot{\mathrm{N}}\)
2. \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \ddot{\mathrm{NH}}_2\)
3. \(\mathrm{CH}_3 \mathrm{CH}_2 \ddot{\mathrm{N}} \mathrm{HCH}_3\)
Options:
1. \(\left(\mathrm{CH}_3\right)_3 \ddot{\mathrm{N}}\)
2. \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \ddot{\mathrm{NH}}_2\)
3. \(\mathrm{CH}_3 \mathrm{CH}_2 \ddot{\mathrm{N}} \mathrm{HCH}_3\)
Solution:
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Verified Answer
The correct answer is:
\(2>3>1\)
Like alkanes dominating inter-molecular force for association of amines to its liquid state is van der Waals' force. We know,
\(\text {van der Waals' force } \propto \frac{1}{\text { branching of chain }} \propto \text { boiling point }\)
Boiling point
\(\text {van der Waals' force } \propto \frac{1}{\text { branching of chain }} \propto \text { boiling point }\)
Boiling point
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