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Question: Answered & Verified by Expert
The orthogonal trajectory of \( x^{2}-y^{2}=a^{2} \), where \( a \) is an arbitrary constant, is
MathematicsDifferential EquationsJEE Main
Options:
  • A A parabola
  • B A circle
  • C An ellipse
  • D A hyperbola
Solution:
2207 Upvotes Verified Answer
The correct answer is: A hyperbola
x2 – y2 = a2
2 x - 2 y dy dx = 0
dy dx = x y
Product of slope of x 2 y 2 = a 2 and slope of orthogonal trajectory of x 2 y 2 = a 2 is 1
Slope of orthogonal trajectory of x 2 y 2 = a 2 is
dy dx = y x
dx x = - dy y
⇒ logx = – logy + logc
logxy = logc
⇒ xy = c
which is a rectangular hyperbola.

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