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The osmotic pressure of blood is 8.21 atm at $37^{\circ} \mathrm{C}$. How much glucose would be used for an injection that is at the same osmotic pressure as blood?
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$58.14 \mathrm{gL}^{-1}$
$\begin{aligned} \pi & =C R T \text { or } C=\frac{\pi}{R T} \\ & =8.21 \mathrm{~atm} / 0.0821 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1} \times 310 \mathrm{~K} \\ & =0.323 \mathrm{M}=0.323 \times 180 \mathrm{gL}^{-1} \\ & =58.14 \mathrm{gL}^{-1}\end{aligned}$
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