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Question: Answered & Verified by Expert
The output for the given, circuit is

PhysicsSemiconductorsAIIMSAIIMS 2016
Options:
  • A $(A+B) \cdot \bar{B}$
  • B $(A \cdot B) \cdot \bar{B}$
  • C $(A+B) \cdot B$
  • D $(A \cdot B)+B$
Solution:
2172 Upvotes Verified Answer
The correct answer is: $(A+B) \cdot \bar{B}$


Here $Y^{\prime}=A+B$
and $Y=Y^{\prime} \cdot \bar{B}=(A+B) \cdot \bar{B}$

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