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The oxidation state and covalency of $\mathrm{Al}$ in $\left[\mathrm{AlCl}\left(\mathrm{H}_2 \mathrm{O}\right)_5\right]^{2+}$ are respectively
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The correct answer is:
$+3,6$
$$
\left[\mathrm{AlCl}\left(\mathrm{H}_2 \mathrm{O}\right)_5\right]^{2+}
$$
Let oxidation state of $\mathrm{Al}$ is $\mathrm{x}$.
$$
\begin{aligned}
& x+(-1)+5(0)=+2, \\
& x=+3
\end{aligned}
$$
Covalency of $\mathrm{Cl}=1$, covalency of $\mathrm{H}_2 \mathrm{O}=5$
$\therefore$ Total covalency $=1+5=6$
\left[\mathrm{AlCl}\left(\mathrm{H}_2 \mathrm{O}\right)_5\right]^{2+}
$$
Let oxidation state of $\mathrm{Al}$ is $\mathrm{x}$.
$$
\begin{aligned}
& x+(-1)+5(0)=+2, \\
& x=+3
\end{aligned}
$$
Covalency of $\mathrm{Cl}=1$, covalency of $\mathrm{H}_2 \mathrm{O}=5$
$\therefore$ Total covalency $=1+5=6$
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