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The oxidation state $(n)$ and coordination number $(\mathrm{CN})$ of $\mathrm{Al}$ and number of valence electrons around $\mathrm{Al}(\mathrm{N})$ in $\mathrm{Al}_2 \mathrm{Cl}_6$ are respectively
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Verified Answer
The correct answer is:
$3,4,8$
$$
\text { Structure of } \mathrm{Al}_2 \mathrm{Cl}_6 \text { is }
$$
Therefore,
(i) Oxidation state $(x)$ of 'Al' in $\mathrm{Al}_2 \mathrm{Cl}$ :
$$
=2 x-6=0 \text { or } x=\{+\rangle
$$
(ii) Coordination number of $\mathrm{Al}$ in $\mathrm{Al}_2 \mathrm{Cl}_5$ is four (4), it is bonded to 4 chlorine atoms in $\mathrm{Al}_2 \mathrm{Cl}_5$.
(iii) Number of valence electrons around Al in
$$
\mathrm{Al}_2 \mathrm{Cl}_6=2 \times 4=8
$$
Hence, option (2) is the correct answer.
\text { Structure of } \mathrm{Al}_2 \mathrm{Cl}_6 \text { is }
$$
Therefore,
(i) Oxidation state $(x)$ of 'Al' in $\mathrm{Al}_2 \mathrm{Cl}$ :
$$
=2 x-6=0 \text { or } x=\{+\rangle
$$
(ii) Coordination number of $\mathrm{Al}$ in $\mathrm{Al}_2 \mathrm{Cl}_5$ is four (4), it is bonded to 4 chlorine atoms in $\mathrm{Al}_2 \mathrm{Cl}_5$.
(iii) Number of valence electrons around Al in
$$
\mathrm{Al}_2 \mathrm{Cl}_6=2 \times 4=8
$$
Hence, option (2) is the correct answer.
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