The oxidation state of Cr in Cr 2 O 7 2 − is, 4, − 6, 6, − 2

Cr 2 O 7 2 − 2 x − 2 × 7 = − 2 ; 2 x = 14 − 2 = 12 x = 2 12 = + 6.

The oxidation state of Cr in Cr 2 O 7 2 − is

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The oxidation state of $\mathrm{Cr}$ in $\mathrm{Cr}_2 \mathrm{O}_7^{2-}$ is

ChemistryRedox ReactionsJEE Main

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The correct answer is: $6$

$\begin{aligned} & \mathrm{Cr}_2 \mathrm{O}_7^{2-} \\ & 2 x-2 \times 7=-2 ; \quad 2 x=14-2=12 \\ & x=\frac{12}{2}=+6 .\end{aligned}$

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