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Question: Answered & Verified by Expert
The oxidation states of 'P' in H4P2O7, H4P2O5 and H4P2O6, respectively, are :
ChemistryRedox ReactionsJEE MainJEE Main 2021 (27 Jul Shift 1)
Options:
  • A 7, 5 and 6
  • B 5, 4 and 3
  • C 5, 3 and 4
  • D 6, 4 and 5
Solution:
2013 Upvotes Verified Answer
The correct answer is: 5, 3 and 4

Oxidation state of P in H4P2O7, H4P2O5 and H4P2O6 is 5, 3 & 4 respectively 

H4P2O7
2x+4(+1)+7(-2)=0
x=+5
H4P2¯O5
2x+4(+1)+5(-2)=0
x=+3
H4P2¯O6
2x+4(+1)+6(-2)=0
x=+4

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