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The oxide of a metal contains $40 \%$ of oxygen. The valency of metal is 2 . What is the atomic weight of metal?
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Verified Answer
The correct answer is:
$24$
$\because 40 \mathrm{~g}$ of oxygen is combined with $=60 \mathrm{~g}$ of metal
$$
\begin{array}{r}
\therefore 8 \mathrm{~g} \text { of oxygen will be combined with }=\frac{60 \times 8}{40} \\
=12 \mathrm{~g} \text { of metal }
\end{array}
$$
$\therefore$ Equivalent weight of metal $=12$
Now, Atomic weight
$=$ Equivalent weight $\times$ valency
$$
=12 \times 2=24
$$
$$
\begin{array}{r}
\therefore 8 \mathrm{~g} \text { of oxygen will be combined with }=\frac{60 \times 8}{40} \\
=12 \mathrm{~g} \text { of metal }
\end{array}
$$
$\therefore$ Equivalent weight of metal $=12$
Now, Atomic weight
$=$ Equivalent weight $\times$ valency
$$
=12 \times 2=24
$$
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